MATH SOLVE

2 months ago

Q:
# A 10-foot ladder is leaned against a wall. The angle between the base of the ladder and the ground measures 62°. How far up the wall does the ladder reach from the ground rounded to the nearest tenth?

Accepted Solution

A:

To solve this problem you must apply the proccedure shown below:

1. You have that:

- The10-foot ladder is leaned against a wall.

- The angle between the base of the ladder and the ground measures 62°.

2. Therefore, you have:

Sinα=opposite/hypotenuse

α=62°

opposite=x

hypotenuse=10

3. Therefore, when you clear "x", you obtain:

Sin(62°)=x/10

(10)(Sin(62°))=x

x=8.82

How far up the wall does the ladder reach from the ground rounded to the nearest tenth?

The answer is: 8.82 ft

1. You have that:

- The10-foot ladder is leaned against a wall.

- The angle between the base of the ladder and the ground measures 62°.

2. Therefore, you have:

Sinα=opposite/hypotenuse

α=62°

opposite=x

hypotenuse=10

3. Therefore, when you clear "x", you obtain:

Sin(62°)=x/10

(10)(Sin(62°))=x

x=8.82

How far up the wall does the ladder reach from the ground rounded to the nearest tenth?

The answer is: 8.82 ft